18n^2-102n-168=0

Solution for 18n^2-102n-168=0 equation:

18n^2-102n-168=0

a = 18; b = -102; c = -168;
Δ = b2-4ac
Δ = -1022-4·18·(-168)
Δ = 22500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{22500}=150$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-102)-150}{2*18}=\frac{-48}{36}
=-1+1/3
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-102)+150}{2*18}=\frac{252}{36}
=7
$